What is the energy of a photon of light whose frequency is 6.91 x 10^15 Hz?


The energy \( E \) of a photon can be calculated using the equation:

\[
E = h \cdot f
\]

where:
- \( E \) is the energy of the photon,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J·s} \)),
- \( f \) is the frequency of the photon.

Given:
- \( f = 6.91 \times 10^{15} \, \text{Hz} \)

Substituting the values into the equation:

\[
E = (6.626 \times 10^{-34} \, \text{J·s}) \cdot (6.91 \times 10^{15} \, \text{Hz})
\]

Let's calculate it:

\[
E = 4.579 \times 10^{-18} \, \text{J}
\]

So, the energy of the photon is approximately \( 4.579 \times 10^{-18} \, \text{J} \).

Would you like more details or have any questions?

Here are five related questions you could explore:
1. What is the relationship between wavelength and frequency in light?
2. How does photon energy relate to the color of visible light?
3. What is the wavelength of a photon with the given frequency?
4. How is the photoelectric effect related to photon energy?
5. How does photon energy change with frequency?

**Tip**: Higher frequency photons, like X-rays and gamma rays, carry more energy than lower frequency photons, such as visible light or radio waves.

What is the energy of a photon of light whose frequency is 6.91 x 10^15 Hz?

Learn how to calculate the energy of a photon with a frequency of 6.91 x 10^15 Hz using Planck's equation. This detailed solution includes key physics concepts such as photon energy, frequency, and Planck's constant. Ideal for students in Grades 11-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation